C语言实现顺序表的基本操作(简单版)

由于很简单,所以我把注释写的很详细,欢迎大家指正错误!!

#include <stdio.h> #include <malloc.h> #include <assert.h> //创建动态顺序表 typedef struct node { 	int* arr;//指针指向头 	int  szie;//有效元素 	int capacity;//总容量 }node; //1.顺序表初始化 void NodeInit(node* ps, int initcapacity); //2.顺序表释放 void NodeDestory(node* ps); //3.顺序表打印 void NodePrint(node* ps); //4.顺序表尾插 void NodePushback(node* ps, int x); //5.顺序表头插 void NodePushfront(node* ps, int x); //6.顺序表头删 void NodePopfront(node* ps); //7.顺序表尾删 void NodePopback(node* ps); //8.顺序表测试 void Testnode(); int NodeisEmpty(node* ps); //9.判断顺序表是否为空 int NodeisEmpty(node* ps) { 	assert(ps); 	return 0 == ps->szie; } //10.顺序表寻找元素返回下标 int NodeFind(node* ps, int x); //11.顺序表在pos位置插入x void NodeInsert(node* ps, size_t pos, int x); //12.顺序表删除pos位置的元素 void Nodedelet(node* ps, size_t pos); //1.顺序表的初始化 void NodeInit(node* ps, int initcapacity) { 	assert(ps); 	ps->arr = (int*)malloc(sizeof(int) * initcapacity); 	if (NULL == ps->arr) { 		assert(0); 		return; 	} 	ps->capacity = initcapacity; 	ps->szie = 0; } //2.顺序表的释放 void NodeDestory(node* ps) { 	assert(ps); 	if (ps->arr) { 		free(ps->arr); 		ps->capacity = 0; 		ps->szie = 0; 	} } //3.顺序表的打印 void NodePrint(node* ps) { 	assert(ps); 	for (int i = 0; i < ps->szie; i++) { 		printf("%d ", ps->arr[i]); 	} 	printf("\n"); } //4.顺序表的尾插 void NodePushback(node* ps, int x) { 	assert(ps); 	if (ps->capacity > ps->szie) { 		ps->arr[ps->szie] = x; 		ps->szie++; 	} 	else { 		printf("添加失败!\n"); 	} } //5.顺序表的头插 void NodePushfront(node* ps, int x) { 	assert(ps); 	if (ps->capacity > ps->szie) { 		int tmp = ps->arr[0]; 		for (int i = ps->szie - 1; i >= 0; i--) { 			ps->arr[i+1] = ps->arr[i]; 		} 		ps->arr[0] = x; 		ps->szie++; 	} 	else { 		printf("插入失败!\n"); 	}  } //6.顺序表的头删 void NodePopfront(node* ps) { 	assert(ps); 	for (int i = 0; i < ps->szie - 1; i++) { 		ps->arr[i] = ps->arr[i+1]; 	} 	ps->szie--; } //7.顺序表的尾删 void NodePopback(node* ps) { 	if (NodeisEmpty(ps)) { 		return; 	} 	else { 		ps->szie--; 	} } //10.顺序表寻找元素返回下标 int NodeFind(node* ps, int x) { 	assert(ps); 	for (int i = 0; i < ps->szie - 1; i++) { 		if (ps->arr[i] == x) { 			return i; 		} 	} 	return -1; } //11.顺序表在pos位置插入x void NodeInsert(node* ps, size_t pos, int x) { 	assert(ps); 	if (ps->capacity > ps->szie) { 		for (int i =ps->szie-1; i >pos-1; i--) { 			ps->arr[i+1] = ps->arr[i]; 		} 		ps->arr[pos] = x; 		ps->szie++; 	} } //12.顺序表删除pos位置的元素 void Nodedelet(node* ps, size_t pos) { 	assert(ps); 	for (int i = pos; i < ps->szie; i++) { 		ps->arr[i] = ps->arr[i+1]; 	} 	ps->szie--; } //测试用例1 void Testnode1() { 	node s;//创建变量 	NodeInit(&s, 10);//初始化 	NodePushback(&s, 1);//尾插1 	NodePushback(&s, 2);//尾插2 	NodePushback(&s, 3);//尾插3 	NodePushback(&s, 4);//尾插4 	NodePushback(&s, 5);//尾插5 	NodePushback(&s, 6);//尾插6	---->顺序表里的数字为1 2 3 4 5 6 	NodePrint(&s); 	NodePopback(&s);//尾删1位元素 	NodePrint(&s); 	NodePushback(&s, 6);//再加回来 	NodePrint(&s); 	NodePushfront(&s, 0);//头插0;								---->顺序表里的数字为0 1 2 3 4 5 6 	NodePrint(&s); 	NodePopfront(&s, 0);//头删0;								---->顺序表里的数字为1 2 3 4 5 6 	NodePrint(&s); 	NodeInsert(&s, 3, 5);//在顺序表下标为3的元素前面插入5		---->顺序表里的数字为1 2 3 5 4 5 6 	NodePrint(&s); 	Nodedelet(&s, 3);//删除下标为3的元素 	NodePrint(&s); 	NodePrint(&s); 	printf("找到数字3的下标为%d\n", NodeFind(&s, 3));//找到3所对应的下标 	NodeDestory(&s); 	NodePrint(&s); } void Testnode() { 	Testnode1(); } int main() { 	Testnode(); 	return 0; }

 运行结果如下:

 非常简单,学会的扣1,没学会的扣眼珠子.